Best plotly equivalent to sns.distplot(data, fit=norm)

Hello there.

I’m trying to find the best, quickest equivalent possible to the following seaborn snippet:

import seaborn as sns
from scipy.stats import norm

sns.distplot(data, fit=norm)

This allows me to fit the normal to an existent displot in seaborn in a very handy manner. What would be the best equivalent in plotly?

Thanks for your time

Hi @jralfonsog,

Welcome to Plotly forum!!
Plotly provides the function plotly.figure_factory.create_distplot() to generate a distplot, that can display the histogram, the pdf estimate, and the rug plot:

create_distplot(hist_data, group_labels, bin_size=1.0, curve_type='kde', colors=None, rug_text=None, histnorm='probability density', show_hist=True, show_curve=True, show_rug=True)

This function works with multiple data sets. If you want to plot just the distplot associated to a single sample,
x= [n values], then pass to hist_data, [x], i.e. a list of a list, not just x.


import plotly.figure_factory as ff
import numpy as np
x = np.random.normal(loc=2.5, scale=0.85, size=300) 
group_labels = 'My sample'

# Create distplot with custom bin_size, and without rug plot
fig = ff.create_distplot([x], [group_labels], bin_size=.2, show_rug=False)


If we set above, show_rug=True, we get:


For more information on this function type:


and here you can find more examples, but with no settings to ensure plot aesthetics (i.e. they are plotted with default layout.width and layout.height, and the bargap is not set, as i did above). That’s why the histograms look like a continuum, not like in these seaborn examples
Hence you should customize the figure appearance.


(Late) thanks for your response, @empet

I’m familiar with ff.create_displot(). What I would like to do would similar to being able to plot “kde” and “normal” curve types at the same time. I guess I could do something like:

import plotly.figure_factory as ff
from scipy.stats import norm
import numpy as np

data = np.random.noncentral_chisquare(3, 20, 1000)

m, s =
gaussian_data = np.random.normal(m, s, 10000)

fig = ff.create_distplot(
    [data, gaussian_data],
    group_labels=["plot", "gaussian"],

But, in this case:

  • I would have to print the gaussian histogram, and I would rather not to (AFAIK, you can’t choose not to print histogram just for a specific element of hist_data).
  • I would have to pick a big number of random gaussian samples to ensure a proper gaussian visualization.

On the other side, ff.create_displot says it’s deprecated in favor of px.histogram, but I can’t find a way of plotting kde easily with px.histogram.

Thanks a lot for your time.


When I answered your question, ff.create_distplot() wasn’t declared “deprecated”. Reading the attribute description in help(px.histogram) it doesn’t seem that px.histogram have an option for density estimation, via kde. @nicolaskruchten could you please give more details to @jralfonsog on this aspect?

You’re right, we don’t have KDE functionality within px.histogram yet, so for those uses I would recommend either computing the KDE line outside of plotly and using px.histogram().add_trace() or continuing to use ff.create_distplot() keeping in mind that we’re not maintaining it much any more.

At some point in the hopefully-near future we will add the KDE functionality to px.histogram() … assistance is very welcome if someone wants to pitch in with a PR! Happy to discuss the design I have in mind!

Thanks both @empet and @nicolaskruchten for your answers. I’ll give the add_trace() way a look, and I’ll let you know.

Maybe not strictly a plotly question, but I’ve not been able to properly compute KDE and add it as a plotly trace to px.histogram(). Could any of you please give me some help? (An example would probably work perfectly)