How to cut a convexhull by a surface

📊 Plotly Python
1

Hello everyone, I have built a convexhull from a list of points using the ConvexHully function of scipy.spatial

H=ConvexHull(points)
    PH=H.points
    vh=H.vertices
    sh=H.simplices 
  go.Mesh3d(x=PH[:, 0],y=PH[:, 1], z=PH[:, 2], 
                        name='Hull',
                        showlegend=True,
                        color='gray', 
                     i=sh[:, 0], j=sh[:, 1], k=sh[:, 2],
                        opacity=1,
                        alphahull=1,
                        showscale=False)

and on the other hand I have drawn a surface from a grid, using go.Surface.

   tx=grid[0]
    ty=grid[1]
    tz=grid[2]

    X = np.linspace(min(tx), max(tx))
    Y = np.linspace(min(ty), max(ty))
    X, Y = np.meshgrid(X, Y) 
    Z = griddata((tx,ty),tz,(X,Y), method='linear)
  go.Surface( x=X,y=Y,z=Z,
                           colorscale=blues,
                           opacity = 1,
                           name='Topography',
                           showlegend=True,
                           showscale=False)

Captura de pantalla 2023-07-21 a las 7.54.13
Captura de pantalla 2023-07-21 a las 7.54.131288×878 46.2 KB

I would like to erase the part of the convexhull that is above the surface.

Any suggestions?
Thanks

2

If you have control at the vertex level on X,Y,Z (which seems to be from the code), just clamp the proper axis with either a math library function or hand-roll your own.

Fancier things would require collision checking/vector math/minkowski difference kind of solutions.