@meteoDan

This a question for `gis.stackexchange`

. Here we can only suggest how to draw on a Scattermapbox chart, a line representing a circle, once you found out its equation in lon and lat coordinates used by Mapbox

Here is the code for plotting a circle as in a cartesian system with lon, lat interpreted as x, y coordinates It can be used as model when you have found out the actual parametric equation:

```
import numpy as np
from numpy import pi, sin, cos
import plotly.graph_objs as go
fig = go.Figure(go.Scattermapbox(
lat=[45.46427],
lon=[9.18951],
mode='markers',
text='Milan',
marker_size=9, marker_color='red',
hoverinfo='text'))
R = 0.75
center_lon = 9.18951
center_lat = 45.46427
t = np.linspace(0, 2*pi, 100)
circle_lon =center_lon + R*cos(t)
circle_lat =center_lat + R*sin(t)
coords=[]
for lo, la in zip(list(circle_lon), list(circle_lat)):
coords.append([lo, la])
layers=[dict(sourcetype = 'geojson',
source={ "type": "Feature",
"geometry": {"type": "LineString",
"coordinates": coords
}
},
color= 'red',
type = 'line',
line=dict(width=1.5)
)]
fig.update_layout(
title_text='Your title',
width=850,
height=850,
mapbox=dict(
accesstoken=mapbox_access_token,
layers=layers,
bearing=0,
center=dict(
lat=45.8257,
lon=10.8746,
),
pitch=0,
zoom=5.6,
style='outdoors')
)
```