Hey @matt.sd.watson welcome to the forums.
I extracted the coordinates like this in the past:
import re
def extract(closedpath: str) -> list[float]:
path = re.split('[a-zA-Z]', closedpath)
path = [point for point in path if point]
# initiate variables
x = []
y = []
for point in path:
point_x, point_y = map(float, point.split(','))
x.append(point_x)
y.append(point_y)
return x,y
usage:
string = "M291.94094488188983,299.9798228346457L314.61811023622056,277.30265748031496L351.468503937008,277.30265748031496L367.53149606299223,283.91683070866145L387.3740157480316,290.5310039370079L404.3818897637796,307.5388779527559Z"
x, y = extract(string)
As for the second part of your question, this might be helpful:
Search for the text passage:
we use the function skimage.draw.polygon to obtain the coordinates of pixels covered by the path
then we use the function scipy.ndimage.binary_fill_holes in order to set to True the pixels enclosed by the path.
EDIT: reading the linked example it sounds pretty similar to what you want to do…